(x+y)(5x^2-3xy+7y^2)=0

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Solution for (x+y)(5x^2-3xy+7y^2)=0 equation: 


Simplifying
(x + y)(5x2 + -3xy + 7y2) = 0

Reorder the terms:
(x + y)(-3xy + 5x2 + 7y2) = 0

Multiply (x + y) * (-3xy + 5x2 + 7y2)
(x(-3xy + 5x2 + 7y2) + y(-3xy + 5x2 + 7y2)) = 0
((-3xy * x + 5x2 * x + 7y2 * x) + y(-3xy + 5x2 + 7y2)) = 0

Reorder the terms:
((7xy2 + -3x2y + 5x3) + y(-3xy + 5x2 + 7y2)) = 0
((7xy2 + -3x2y + 5x3) + y(-3xy + 5x2 + 7y2)) = 0
(7xy2 + -3x2y + 5x3 + (-3xy * y + 5x2 * y + 7y2 * y)) = 0
(7xy2 + -3x2y + 5x3 + (-3xy2 + 5x2y + 7y3)) = 0

Reorder the terms:
(7xy2 + -3xy2 + -3x2y + 5x2y + 5x3 + 7y3) = 0

Combine like terms: 7xy2 + -3xy2 = 4xy2
(4xy2 + -3x2y + 5x2y + 5x3 + 7y3) = 0

Combine like terms: -3x2y + 5x2y = 2x2y
(4xy2 + 2x2y + 5x3 + 7y3) = 0

Solving
4xy2 + 2x2y + 5x3 + 7y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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